Passing a command with arguments to a script

I am trying to write a shell script that receives as an input a command with arguments and runs it.

I am hoping to use this in cron as follows:

0 11 * * * my_wrapper.sh "task_name" "command arg1 arg2 arg3 ..."

Note that, as I put it above, my_wrapper.sh receives two arguments:

1. task_name as a string


2. command arg1 arg2 arg3

The goal is to have my_wrapper.sh:

1. Run command arg1 arg2 arg3 ...*


2. Record the output of the command in a log file with filename task_name

I am hoping to write my_wrapper.sh using zsh.

My questions are:

• What is the proper way of passing and receiving parameters to my_wrapper.sh


• Will I be able to handle any type of command arg1 arg2 arg3? (quotes, etc.)

Needless to say, the following doesn't work:

#!/usr/bin/zsh
task_name=$1 
command_to_run=$2